Integrand size = 41, antiderivative size = 170 \[ \int \frac {\tan ^m(c+d x) \left (A+B \tan (c+d x)+C \tan ^2(c+d x)\right )}{\sqrt {b \tan (c+d x)}} \, dx=\frac {2 C \tan ^{1+m}(c+d x)}{d (1+2 m) \sqrt {b \tan (c+d x)}}+\frac {2 (A-C) \operatorname {Hypergeometric2F1}\left (1,\frac {1}{4} (1+2 m),\frac {1}{4} (5+2 m),-\tan ^2(c+d x)\right ) \tan ^{1+m}(c+d x)}{d (1+2 m) \sqrt {b \tan (c+d x)}}+\frac {2 B \operatorname {Hypergeometric2F1}\left (1,\frac {1}{4} (3+2 m),\frac {1}{4} (7+2 m),-\tan ^2(c+d x)\right ) \tan ^{2+m}(c+d x)}{d (3+2 m) \sqrt {b \tan (c+d x)}} \]
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Time = 0.17 (sec) , antiderivative size = 170, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.122, Rules used = {20, 3711, 3619, 3557, 371} \[ \int \frac {\tan ^m(c+d x) \left (A+B \tan (c+d x)+C \tan ^2(c+d x)\right )}{\sqrt {b \tan (c+d x)}} \, dx=\frac {2 (A-C) \tan ^{m+1}(c+d x) \operatorname {Hypergeometric2F1}\left (1,\frac {1}{4} (2 m+1),\frac {1}{4} (2 m+5),-\tan ^2(c+d x)\right )}{d (2 m+1) \sqrt {b \tan (c+d x)}}+\frac {2 B \tan ^{m+2}(c+d x) \operatorname {Hypergeometric2F1}\left (1,\frac {1}{4} (2 m+3),\frac {1}{4} (2 m+7),-\tan ^2(c+d x)\right )}{d (2 m+3) \sqrt {b \tan (c+d x)}}+\frac {2 C \tan ^{m+1}(c+d x)}{d (2 m+1) \sqrt {b \tan (c+d x)}} \]
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Rule 20
Rule 371
Rule 3557
Rule 3619
Rule 3711
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {\tan (c+d x)} \int \tan ^{-\frac {1}{2}+m}(c+d x) \left (A+B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx}{\sqrt {b \tan (c+d x)}} \\ & = \frac {2 C \tan ^{1+m}(c+d x)}{d (1+2 m) \sqrt {b \tan (c+d x)}}+\frac {\sqrt {\tan (c+d x)} \int \tan ^{-\frac {1}{2}+m}(c+d x) (A-C+B \tan (c+d x)) \, dx}{\sqrt {b \tan (c+d x)}} \\ & = \frac {2 C \tan ^{1+m}(c+d x)}{d (1+2 m) \sqrt {b \tan (c+d x)}}+\frac {\left (B \sqrt {\tan (c+d x)}\right ) \int \tan ^{\frac {1}{2}+m}(c+d x) \, dx}{\sqrt {b \tan (c+d x)}}+\frac {\left ((A-C) \sqrt {\tan (c+d x)}\right ) \int \tan ^{-\frac {1}{2}+m}(c+d x) \, dx}{\sqrt {b \tan (c+d x)}} \\ & = \frac {2 C \tan ^{1+m}(c+d x)}{d (1+2 m) \sqrt {b \tan (c+d x)}}+\frac {\left (B \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {x^{\frac {1}{2}+m}}{1+x^2} \, dx,x,\tan (c+d x)\right )}{d \sqrt {b \tan (c+d x)}}+\frac {\left ((A-C) \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {x^{-\frac {1}{2}+m}}{1+x^2} \, dx,x,\tan (c+d x)\right )}{d \sqrt {b \tan (c+d x)}} \\ & = \frac {2 C \tan ^{1+m}(c+d x)}{d (1+2 m) \sqrt {b \tan (c+d x)}}+\frac {2 (A-C) \operatorname {Hypergeometric2F1}\left (1,\frac {1}{4} (1+2 m),\frac {1}{4} (5+2 m),-\tan ^2(c+d x)\right ) \tan ^{1+m}(c+d x)}{d (1+2 m) \sqrt {b \tan (c+d x)}}+\frac {2 B \operatorname {Hypergeometric2F1}\left (1,\frac {1}{4} (3+2 m),\frac {1}{4} (7+2 m),-\tan ^2(c+d x)\right ) \tan ^{2+m}(c+d x)}{d (3+2 m) \sqrt {b \tan (c+d x)}} \\ \end{align*}
Time = 0.53 (sec) , antiderivative size = 133, normalized size of antiderivative = 0.78 \[ \int \frac {\tan ^m(c+d x) \left (A+B \tan (c+d x)+C \tan ^2(c+d x)\right )}{\sqrt {b \tan (c+d x)}} \, dx=\frac {2 \tan ^{1+m}(c+d x) \left (C (3+2 m)+(A-C) (3+2 m) \operatorname {Hypergeometric2F1}\left (1,\frac {1}{4} (1+2 m),\frac {1}{4} (5+2 m),-\tan ^2(c+d x)\right )+B (1+2 m) \operatorname {Hypergeometric2F1}\left (1,\frac {1}{4} (3+2 m),\frac {1}{4} (7+2 m),-\tan ^2(c+d x)\right ) \tan (c+d x)\right )}{d (1+2 m) (3+2 m) \sqrt {b \tan (c+d x)}} \]
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\[\int \frac {\tan \left (d x +c \right )^{m} \left (A +B \tan \left (d x +c \right )+C \tan \left (d x +c \right )^{2}\right )}{\sqrt {b \tan \left (d x +c \right )}}d x\]
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\[ \int \frac {\tan ^m(c+d x) \left (A+B \tan (c+d x)+C \tan ^2(c+d x)\right )}{\sqrt {b \tan (c+d x)}} \, dx=\int { \frac {{\left (C \tan \left (d x + c\right )^{2} + B \tan \left (d x + c\right ) + A\right )} \tan \left (d x + c\right )^{m}}{\sqrt {b \tan \left (d x + c\right )}} \,d x } \]
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\[ \int \frac {\tan ^m(c+d x) \left (A+B \tan (c+d x)+C \tan ^2(c+d x)\right )}{\sqrt {b \tan (c+d x)}} \, dx=\int \frac {\left (A + B \tan {\left (c + d x \right )} + C \tan ^{2}{\left (c + d x \right )}\right ) \tan ^{m}{\left (c + d x \right )}}{\sqrt {b \tan {\left (c + d x \right )}}}\, dx \]
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Timed out. \[ \int \frac {\tan ^m(c+d x) \left (A+B \tan (c+d x)+C \tan ^2(c+d x)\right )}{\sqrt {b \tan (c+d x)}} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {\tan ^m(c+d x) \left (A+B \tan (c+d x)+C \tan ^2(c+d x)\right )}{\sqrt {b \tan (c+d x)}} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {\tan ^m(c+d x) \left (A+B \tan (c+d x)+C \tan ^2(c+d x)\right )}{\sqrt {b \tan (c+d x)}} \, dx=\int \frac {{\mathrm {tan}\left (c+d\,x\right )}^m\,\left (C\,{\mathrm {tan}\left (c+d\,x\right )}^2+B\,\mathrm {tan}\left (c+d\,x\right )+A\right )}{\sqrt {b\,\mathrm {tan}\left (c+d\,x\right )}} \,d x \]
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